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1.5x^2-6x+5=0
a = 1.5; b = -6; c = +5;
Δ = b2-4ac
Δ = -62-4·1.5·5
Δ = 6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{6}}{2*1.5}=\frac{6-\sqrt{6}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{6}}{2*1.5}=\frac{6+\sqrt{6}}{3} $
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